So i did a lab today and i have to find the theoretical yield of copper i know how to find the theoretical yield im just a little confused here is are my results for the lab
Mass of Mg used: 0.301
Moles of Mg used:1.248 *10^-2
Mass of Copper produced:.118 grams
Moles of Copper produced:1.85 *10^-3
Mg/copper mole ratio: 7:1
Correct equation: Mg(s)+CuSO4--- MgSO4 +Cu
all I am missing is the theoretical, actual and percent yeild. I need some guidance Please =)

Question

So i did a lab today and i have to find the theoretical yield of copper i know how to find the theoretical yield im just a little confused here is  are my results for the lab 
Mass of Mg used: 0.301
Moles of Mg used:1.248 *10^-2
Mass of Copper produced:.118 grams
Moles of Copper produced:1.85 *10^-3 
Mg/copper mole ratio: 7:1
Correct equation: Mg(s)+CuSO4---> MgSO4 +Cu 
 all I am missing is the theoretical, actual and percent yeild. I need some guidance Please =)

rachie19 · Answer

mass of copper produced should be .118 grams

photon336 · Answer

So the theoretical yield is like how many grams of products you would expect based from the chemical reaction

photon336 · Answer

Experimental yield is what you get from doing the lab

rachie19 · Answer

ok so 2Cu? would be what i would use

photon336 · Answer

You mean CuSO4 right? Limiting reagent can only be one of the reactant(s) what you start out with