Suppose the integral from 2 to 8 of g of x, dx equals 13, and the integral from 6 to 8 of g of x, dx equals negative 3, find the value of 2 plus the integral from 2 to 6 of g of x, dx.

Question

anonymous · Answer

https://gyazo.com/41bc06711b55841c5edc26d60f3d956a

freckles · Answer

$$\int\limits_2^6g(x) dx=\int\limits_2^8 g(x) dx- \int\limits_6^8 g(x)dx$$

freckles · Answer

we have from 2 to 8 given
but we wanted 2 to 6 so we have to subtract the part out that is from 6 to 8

freckles · Answer

which is given also

freckles · Answer

don't forget to add the 2 in

anonymous · Answer

So how would go about to solve? Solve each integral then subtract?

anonymous · Answer

no just subtract

anonymous · Answer

Oooooooooohhhhhhh
I'm an idiot, read the question so wrong. 16+2=18
Final answer 18 right?

freckles · Answer

right
you have 2+13-(-3)
which is 15+3
which is 18