Find the x-intercepts (if any) for the graph of the quadratic function.
6x2 + 12x + 5 = 0
Give your answers in exact form. Show your work.
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OpenStudy (anonymous):
@Hero @dan815
OpenStudy (anonymous):
@Jhannybean @satellite73 @Loser66 @freckles @EclipsedStar @King.Void. @sleepyjess can someone help me please?
OpenStudy (sleepyjess):
Do you have an idea on how to start?
OpenStudy (anonymous):
no not at all
OpenStudy (sleepyjess):
Do you know what the quadratic formula is?
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OpenStudy (anonymous):
what you mean?
OpenStudy (sleepyjess):
\(x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\)
OpenStudy (sleepyjess):
That is the quadratic formula
OpenStudy (sleepyjess):
It may look intimidating, but it's not too bad once you know how to work it :)
OpenStudy (anonymous):
Okay how do I work it lol..
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OpenStudy (sleepyjess):
A quadratic equation is ALWAYS "Ax^2 + Bx + C = y"
To use the quadratic formula, you will want to substitute 0 for y, which has already been done.
Can you figure out what A, B, and C are in the quadratic equation you have?
OpenStudy (anonymous):
A= 6x^2
B= 12x
C= 5
OpenStudy (sleepyjess):
Close, but we just want 6, 12 and 5
OpenStudy (anonymous):
Ohh lol
OpenStudy (sleepyjess):
So now we just substitute in 6 for a, 12 for b, and 5 for c
then work out the equation
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OpenStudy (anonymous):
I got down to \[x= \frac{ -12\pm \sqrt{24} }{ 12 }\] now what do I do?
OpenStudy (anonymous):
@sleepyjess
OpenStudy (carolinar7):
Now simplify what you have there
OpenStudy (anonymous):
How?
OpenStudy (carolinar7):
\[x=\frac{ -12-+4\sqrt{6} }{ 12 }\]
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OpenStudy (carolinar7):
Can you simplify any further?
OpenStudy (anonymous):
Why 4 sqrt7 instead of sqrt24=4.89....?
OpenStudy (anonymous):
I meant sqrt6 sorry
OpenStudy (carolinar7):
Sorry let me correct myself it is 2sqrt6
OpenStudy (carolinar7):
Is this Alg. 1
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OpenStudy (anonymous):
How!? And no its pre-calculus
OpenStudy (carolinar7):
what grade ar you in
OpenStudy (anonymous):
@sleepyjess please help me, I don't understand!!
OpenStudy (carolinar7):
me too im in pre-calc in 9th grade
OpenStudy (sleepyjess):
oh goodness, I forgot about the square root simplifying >_<
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OpenStudy (anonymous):
How do I do that?
OpenStudy (sleepyjess):
@carolinar7 simplified it for you
OpenStudy (carolinar7):
what do you mean you simplified it for me
OpenStudy (sleepyjess):
you simplified the square root already
OpenStudy (anonymous):
2 sqrt6?
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OpenStudy (carolinar7):
It is not completely simplified though, you can simplify further too
OpenStudy (carolinar7):
\[x=\frac{ -6+-\sqrt{6} }{ 6 }\]
OpenStudy (anonymous):
so where do I go from \[x= \frac{ -12 \pm 2\sqrt{6} }{ 12 }\]
OpenStudy (anonymous):
Ohhh how did you get that?
OpenStudy (carolinar7):
You simplify it and divide by 2 because that is what they share in common
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