Three airlines serve a small town in Ohio. Airline A has 46% of all scheduled flights, airline B has 35% and airline C has the remaining 19%. Their on-time rates are 79%, 66%, and 39%, respectively. A flight just left on-time. What is the probability that it was a flight of airline A? Probability =
okay
@dan815 How do you find the Probability of that though?
Lets take a look at number of flights that are on time
suppose instead of percents you think of it as just having 46,35 and 19 planes now you know that 76%,66% and 39% of each of those respectively will be on time
ok
what does it mean for the number flights we are talking about here
76% of the 46 is on time for flight A how many total flights are on time that is 46*76% + 35*66%+19*39% therefore the prob that a flight was ontime and is A is = on time A flights/Total On time flights =46*76%/(46*76% + 35*66%+19*39%)
I tried doing something similar to that earlier, ill try it now
i can help you understand it conceptually if its not making sense
now it makes sense. My brain is complete fried I Have not slept for over a day and possibly looking at a back to back all nighters. I have a mid-term tomorrow that I know Little about
oh okay, good luck
thanks
@dan815 Is the answer .3634/.6685
i dont know its just that expression
It was RIGHT!! Thank you :D
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