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Mathematics 18 Online
OpenStudy (pulsified333):

Three airlines serve a small town in Ohio. Airline A has 46% of all scheduled flights, airline B has 35% and airline C has the remaining 19%. Their on-time rates are 79%, 66%, and 39%, respectively. A flight just left on-time. What is the probability that it was a flight of airline A? Probability =

OpenStudy (dan815):

okay

OpenStudy (pulsified333):

@dan815 How do you find the Probability of that though?

OpenStudy (dan815):

Lets take a look at number of flights that are on time

OpenStudy (dan815):

suppose instead of percents you think of it as just having 46,35 and 19 planes now you know that 76%,66% and 39% of each of those respectively will be on time

OpenStudy (pulsified333):

ok

OpenStudy (dan815):

what does it mean for the number flights we are talking about here

OpenStudy (dan815):

76% of the 46 is on time for flight A how many total flights are on time that is 46*76% + 35*66%+19*39% therefore the prob that a flight was ontime and is A is = on time A flights/Total On time flights =46*76%/(46*76% + 35*66%+19*39%)

OpenStudy (pulsified333):

I tried doing something similar to that earlier, ill try it now

OpenStudy (dan815):

i can help you understand it conceptually if its not making sense

OpenStudy (pulsified333):

now it makes sense. My brain is complete fried I Have not slept for over a day and possibly looking at a back to back all nighters. I have a mid-term tomorrow that I know Little about

OpenStudy (dan815):

oh okay, good luck

OpenStudy (pulsified333):

thanks

OpenStudy (pulsified333):

@dan815 Is the answer .3634/.6685

OpenStudy (dan815):

i dont know its just that expression

OpenStudy (pulsified333):

It was RIGHT!! Thank you :D

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