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Algebra 18 Online
OpenStudy (anonymous):

Will give medal for help

OpenStudy (anonymous):

What is the average rate of change from x = –4 to x = 1? –3 –1 0 1

OpenStudy (anonymous):

OpenStudy (jhannybean):

Average rate of change = \(\dfrac{f(x)-f(a)}{x-a}\)

OpenStudy (jhannybean):

So your function is shifted to the left an its vertex is at (-1,5) How can we write that?

OpenStudy (jhannybean):

This might help.

OpenStudy (anonymous):

so -4-(-1) 1-5

OpenStudy (anonymous):

is that right ^^^^^

OpenStudy (anonymous):

you there?

OpenStudy (jhannybean):

No that's not correct.

OpenStudy (anonymous):

what did i do wrong?

OpenStudy (jhannybean):

We need to find our function first.

OpenStudy (jhannybean):

So if your graph is shifted 1 unit to the left and 5 units down, then you would write it as \(f(x) = (x\color{red}{+}1)^2\color{red}{-5}\)

OpenStudy (jhannybean):

Do you see what I mean?

OpenStudy (anonymous):

kind of

OpenStudy (anonymous):

@hartnn

OpenStudy (mathstudent55):

The average change form x = a to x = b is \(\dfrac{f(b) - f(a)}{b - a}\)

OpenStudy (mathstudent55):

You want the average change from x = -4 to x = 1. It is important to keep the order in m ind. You don't want the average change from x = 1 to x = -4.

OpenStudy (anonymous):

1 right

OpenStudy (mathstudent55):

Find f(-4) and f(1). You can do this by looking in the graph. What is the y-coordinate where x = -4? What is the y-coordinate where x = 1?

OpenStudy (anonymous):

y= 1 then right

OpenStudy (mathstudent55):

In your case, a = -4, and b = 1, so From the graph: f(-4) = 4 f(1) = -1 \(\dfrac{f(1) - f(-4)}{1 - (-4)}\) \(=\dfrac{-1 - 4}{1 + 4}\)

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