Question

Find the equation of the tangent line to the curve at the given point.
y = 5x − 2squarerootx, (1, 3)

Answer 1

Can you find the first derivative of the function?

Answer 2

@ElfQueen Hello. Are you there?

Answer 3

You may find the first derivative and then find f'(1) which will give you your slope, and then use the following equation \[y-y_1=m(x-x_1)\]

Answer 4

@Mertsj Sorry. I was making myself dinner. I got 5 - 1over the squareroot x.

Answer 5

That's correct \[f'(x) = 5-\frac{ 1 }{ \sqrt{x} }\] now find f'(1)

Answer 6

4

Answer 7

Yes! So our slope is 4, now we can use the point slope equation and we will have our equation

Answer 8

4x-1

Answer 9

I'm not sure what that means, we just have to use \[y-y_1=m(x-x_1)\] and we are given the point (x1,y1)