Find the equation of the tangent line to the curve at the given point.
y = 5x − 2squarerootx, (1, 3)

Question

Find the equation of the tangent line to the curve at the given point.
y = 5x − 2squarerootx, (1, 3)

mertsj · Answer

Can you find the first derivative of the function?

mertsj · Answer

@ElfQueen Hello.  Are you there?

anonymous · Answer

You may find the first derivative and then find f'(1) which will give you your slope, and then use the following equation $$y-y_1=m(x-x_1)$$

anonymous · Answer

@Mertsj Sorry. I was making myself dinner. I got 5 - 1over the squareroot x.

anonymous · Answer

That's correct $$f'(x) = 5-\frac{ 1 }{ \sqrt{x} }$$ now find f'(1)

anonymous · Answer

4

anonymous · Answer

Yes! So our slope is 4, now we can use the point slope equation and we will have our equation

anonymous · Answer

4x-1

anonymous · Answer

I'm not sure what that means, we just have to use $$y-y_1=m(x-x_1)$$ and we are given the point (x1,y1)