a ladder 6 m long leans against a vertical wall. The lower end of the ladder is moved away from he wall at the rate of 2 m/min. Find the rate of change of the area formed by the wall, the floor and the ladder when the lower end is 4 m from the wall. please help
|dw:1443859889821:dw|
It doesnt seem right for some reason
can you think of an equation that connects l and b in your drawing?
|dw:1443860176242:dw|
A=1/2 bh
Using the pythagorean theorem, we can find the rate of change for everything moving
oh boy a ladder problem :)
what is the area if the base?
is 4
You don't necessarily need to know that. You're simply looking for \(\dfrac{dl}{dt}\) when \(x=4\)
how?
Pythagoreas
The area is constantly changing w.r.t time as the ladder moves down the wall
This question you are doing right now, will make or break your mathematical career
Dan... -_-
there's no change in y right? the ladder?
|dw:1443860459057:dw| \[\frac{ dx }{ dt } = 2\] I thought this
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