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Calculus1 7 Online
OpenStudy (jarp0120):

a ladder 6 m long leans against a vertical wall. The lower end of the ladder is moved away from he wall at the rate of 2 m/min. Find the rate of change of the area formed by the wall, the floor and the ladder when the lower end is 4 m from the wall. please help

OpenStudy (jarp0120):

|dw:1443859889821:dw|

OpenStudy (jhannybean):

It doesnt seem right for some reason

OpenStudy (irishboy123):

can you think of an equation that connects l and b in your drawing?

OpenStudy (jarp0120):

|dw:1443860176242:dw|

OpenStudy (jarp0120):

A=1/2 bh

OpenStudy (jhannybean):

Using the pythagorean theorem, we can find the rate of change for everything moving

OpenStudy (dan815):

oh boy a ladder problem :)

OpenStudy (jarp0120):

what is the area if the base?

OpenStudy (jarp0120):

is 4

OpenStudy (jhannybean):

You don't necessarily need to know that. You're simply looking for \(\dfrac{dl}{dt}\) when \(x=4\)

OpenStudy (jarp0120):

how?

OpenStudy (irishboy123):

Pythagoreas

OpenStudy (jhannybean):

The area is constantly changing w.r.t time as the ladder moves down the wall

OpenStudy (dan815):

This question you are doing right now, will make or break your mathematical career

OpenStudy (jhannybean):

Dan... -_-

OpenStudy (jarp0120):

there's no change in y right? the ladder?

OpenStudy (astrophysics):

|dw:1443860459057:dw| \[\frac{ dx }{ dt } = 2\] I thought this

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