Question

What is the equation of the quadratic graph with a focus of (4, 3) and a directix of y = 13?

Answer 1

@AlexandervonHumboldt2

Answer 2

as the focus is below the directrix then the graph is concave down. line of symmetry is x=4.



distance between the focus and directrix is 2 multiplied by the focal length.
distance is 2b = -10 => focal length is b = -5 units
vertex is (4. 3 - (-5)) => (4. 8)
(x^2−h)=4a(y−k)
(x−4^)2=4*(−5)(y−8)
now simplify all this and get your equation

Answer 3

woops mistake wait

Answer 4

this is correct

distance between the focus and directrix is 2 multiplied by the focal length.
distance is 2b = -10 => focal length is b = -5 units
vertex is (4. 3 - (-5)) => (4. 8)

(x^2−h)=4b(y−k)
(x−4)^2=4*(−5)(y−8)

now simplify all this and get your equation

Answer 5

so do you simplify both of it?

Answer 6

not both you simplify this equation (x−4)^2=4*(−5)(y−8)

Answer 7

= −one twentieth (x − 4)2 + 8

Answer 8

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