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OpenStudy (anonymous):
Given that h(x) = 4x+5 and (h-j)(x) = x-2, find j(x).
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OpenStudy (anonymous):
@freckles
OpenStudy (anonymous):
I think I have an idea, but I don't think it is correct
OpenStudy (anonymous):
Would I do 4(x-2)+5
OpenStudy (mathstudent55):
h(x) = 4x+5 and (h-j)(x) = x-2, find j(x)
(h-j)(x) = h(x) - j(x)
x - 2 = 4x + 5 - j(x)
Solve for j(x)
OpenStudy (anonymous):
Ok. Would that be -7/3 ?
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OpenStudy (mathstudent55):
x - 2 = 4x + 5 - j(x)
Add j(x) to both sides:
j(x) + x - 2 = 4x + 5
Subtract x from both sides & add 2 to both sides:
j(x) = 3x + 7
OpenStudy (anonymous):
Oh ok.. And then once I plug them in together I should get x-2 right?
OpenStudy (mathstudent55):
Let's check.
We must have h(x) - j(x) = x - 2
h(x) = 4x + 5
j(x) = 3x + 7
(h-j)(x) = h(x) - j(x)
= 4x + 5 - (3x + 7)
= 4x + 5 - 3x - 7
= x - 2
OpenStudy (anonymous):
Thank you so much! I thought it was something along the likes of that, but I just wanted to double check.
OpenStudy (mathstudent55):
Yes, but the answer is just j(x) = x - 2
I just plugged it in to check if j(x) = x - 2 was the correct answer.
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OpenStudy (mathstudent55):
You're welcome.
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