Question

Given that f(x) = 2x+1 and g(x) = 3x-2, what value(s) of x are excluded from the domain of (f/g)(x)?

I know how to set it up, but I don't understand the whole "exclusion" of the "domain"

Answer 1

hint: the values excluded from the domain are: the x-values that will make the denominator equal to 0

Answer 2

Yeah like when the = sign has a / across it, right?
Would I divide 2x by 3x and 1 by 2?

Answer 3

nope, we can't do that because of these

Answer 4

don't change the function

Answer 5

Oh right, so how would I do it?

Answer 6

set the denominator equal to 0 and solve for x

Answer 7

so 3x-2=0?

Answer 8

right, so x = ?

Answer 9

which would be 2/3

Answer 10

Would I have to do the same thing to the numbers on the top? like 2x+1=0

Answer 11

nope, just the denominator

Answer 12

remember: when we divide two numbers, the numerator can be anything, but the denominator cannot be 0

Answer 13

Ok, and then I would divide them together? or would I do KCF?

Answer 14

Keep it change it flip it

Answer 15

no, you're done here, you found x = 2/3, that's your answer.

Answer 16

Really?

Answer 17

Oh wow.. Thank you!