Question

How many milligrams of NaOH are required to prepare 10.50dL of solution?

Answer 1

Am I on the right track so far?
N=14.01g
O=16.00g
H=1.008g
NaOH=31.02g

Answer 2

\[10.50dL \times \frac{ 0.10L }{ 1dL} \times \frac{ 1000g }{ 1L } \times \frac{ 1000mg }{ 1g}\]

Milligrams of NaOH before solution=Milligrams of in Solution 0.0

Answer 3

Milligrams of NaOH*

Answer 4

Thanks so much, I completely blanked!

Answer 5

No problem!
Good luck on the rest.