Mathematics
15 Online
OpenStudy (anonymous):
Simplify
1 / (1+a^n) + 1/(1+a^-n)
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OpenStudy (freckles):
hint: multiply that second fraction by a^n/a^n
OpenStudy (anonymous):
Thanks but does it cancel out th denominater for the second fraction
OpenStudy (freckles):
\[1 \cdot a_n=? \\ (1+a^{-n}) \cdot a_n=1 \cdot a_n +a^{-n} \cdot a^{n} =?\]
OpenStudy (anonymous):
Wouldn't it be 1+a as the denimontar
OpenStudy (freckles):
those one n's were suppose to be exponents (not subscipts)
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OpenStudy (freckles):
\[1 \cdot a^n=a^n \\ (1+a^{-n}) \cdot a^n=1 \cdot a^n+a^{-n} a^{n} \text{ by distributive law } \\ \text{ now do you know law of exponents? }\]
OpenStudy (freckles):
if you have the same base and you are multiplying what do you do with the exponents ?
OpenStudy (anonymous):
Add
OpenStudy (freckles):
\[(1+a^{-n})a^n=a^n+a^{-n+n}=?\]
OpenStudy (freckles):
-n+n=?
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OpenStudy (anonymous):
0
OpenStudy (freckles):
right and a^0=?
OpenStudy (anonymous):
One
OpenStudy (freckles):
\[\frac{1}{1+a^{n}}+\frac{a^n}{1+a^{n}}=?\]
OpenStudy (freckles):
you see you have the same denominator
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OpenStudy (freckles):
now you can write as one fraction
OpenStudy (freckles):
\[\frac{1+a^{n}}{1+a^{n}}=?\]
OpenStudy (anonymous):
1
OpenStudy (freckles):
right
and this is of coursing assuming a>0
OpenStudy (freckles):
a could be less than 0 depending on n
we could say a lot about the domain restrictions
lol
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OpenStudy (freckles):
but I'm sure they are just looking for 1
OpenStudy (anonymous):
Ok tysm
OpenStudy (freckles):
np