Mathematics
8 Online
OpenStudy (anonymous):
((x+3)/(30x-42))*((40x-56)/(8))
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OpenStudy (anonymous):
\[\frac{ x+3 }{ 30x-42 }*\frac{ 40x-56 }{ 8 }\]
Nnesha (nnesha):
mango > watermelon
OpenStudy (adi3):
two of the great scientist's pictures!!!!!!!!
OpenStudy (adi3):
@Michele_Laino @IrishBoy123
OpenStudy (adi3):
what a pic
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OpenStudy (adi3):
And the thing is that they both are good at mahts!!!!!!!
OpenStudy (adi3):
sorry
OpenStudy (michele_laino):
thanks! :) @Adi3
OpenStudy (adi3):
np
OpenStudy (adi3):
try cross multiply
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OpenStudy (michele_laino):
@helpme375
please note that your expression can berewritten as follows:
\[\frac{{x + 3}}{{6\left( {5x - 7} \right)}} \cdot \frac{{8\left( {5x - 7} \right)}}{8}\]
OpenStudy (adi3):
try cross multiply
Nnesha (nnesha):
irish was typing so i thought he is going to help you.
OpenStudy (michele_laino):
I think that answer is:
\[\frac{{x + 3}}{6}\]
OpenStudy (anonymous):
how did you get it
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OpenStudy (michele_laino):
when you simplify that expression above, then factors 5x-7 cancel, also factors 8 cancel, so we reamin with (x+3) as numerator and 6 as denominator
OpenStudy (michele_laino):
remain*
OpenStudy (anonymous):
but would you be left with (x+3)/8 after you take away 5x-7
OpenStudy (michele_laino):
here is the right simplification:
|dw:1443971900756:dw|
OpenStudy (anonymous):
okay thanks i got it
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OpenStudy (michele_laino):
:)