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Mathematics 15 Online
OpenStudy (anonymous):

Suppose angle A=pi/3 radians and length of c=10

OpenStudy (anonymous):

hartnn (hartnn):

you have b and c, use pythagoras to find a !

OpenStudy (anonymous):

the interior angles are b=30, and a=60

hartnn (hartnn):

right, so you can also use the fact that, side opposite to 60 degree angle is \(\sqrt 3 /2\) times the hypotenuse

OpenStudy (anonymous):

For the length of a I tried setting up sin60=a/10

hartnn (hartnn):

ok, good going, so a = 10 sin 60 and sin 60 is actually \(\sqrt 3 /2\)

OpenStudy (anonymous):

so i'm a little confused what i'm supposed to do with the Sqrt(3)/2

hartnn (hartnn):

multiply it with 10 \(10 \dfrac{\sqrt 3}{2} = 5 \sqrt 3 \)

OpenStudy (anonymous):

oh I see, so instead of using the 60 degrees we are just multiplying sqrt(3)/2 by 10

hartnn (hartnn):

yeah

OpenStudy (anonymous):

makes sense! Thank you lots :D

hartnn (hartnn):

welcome a lots ^_^

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