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Suppose angle A=pi/3 radians and length of c=10
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you have b and c, use pythagoras to find a !
the interior angles are b=30, and a=60
right, so you can also use the fact that, side opposite to 60 degree angle is \(\sqrt 3 /2\) times the hypotenuse
For the length of a I tried setting up sin60=a/10
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ok, good going, so a = 10 sin 60 and sin 60 is actually \(\sqrt 3 /2\)
so i'm a little confused what i'm supposed to do with the Sqrt(3)/2
multiply it with 10 \(10 \dfrac{\sqrt 3}{2} = 5 \sqrt 3 \)
oh I see, so instead of using the 60 degrees we are just multiplying sqrt(3)/2 by 10
yeah
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makes sense! Thank you lots :D
welcome a lots ^_^
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