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Mathematics 15 Online
OpenStudy (anonymous):

suppose angle B=60 degrees, and length of b=2

OpenStudy (anonymous):

hartnn (hartnn):

what have you tried? :)

OpenStudy (anonymous):

angle a is 30 degrees

OpenStudy (anonymous):

which means b is 60 degrees

hartnn (hartnn):

A=30 is correct, B = 60 is given, go on

OpenStudy (anonymous):

tan30=a/2

OpenStudy (anonymous):

2*tan(30)=a/2

hartnn (hartnn):

a =2 tan 30

OpenStudy (anonymous):

which is 1.15 which is just 1

OpenStudy (anonymous):

they want the exact measures

hartnn (hartnn):

since we are not allowed decimals, whats tan 30 in fraction ?

OpenStudy (anonymous):

1/sqrt3

hartnn (hartnn):

or lets try to get 'c' first using sin B

hartnn (hartnn):

ok, thats correct, so a = 2/\sqrt 3

hartnn (hartnn):

\(a= \dfrac{2}{\sqrt 3 }\)

OpenStudy (anonymous):

so sin60=2/c, 2*sin60,

OpenStudy (anonymous):

sin of 60 degrees is sort(3)/2

OpenStudy (anonymous):

sqrt*

hartnn (hartnn):

yes sqrt 3/2 = 2/c so c = 2*2/ sqrt 3 = ...

OpenStudy (anonymous):

4/sqrt(3)

hartnn (hartnn):

\(\huge \checkmark \)

OpenStudy (anonymous):

so basically we are transforming the degrees into the coordinates of either sin or cos .. i'm slow :)

hartnn (hartnn):

i didn't get that :P we are trying to find the missing angles and sides of a triangles using sin/cos/tan ....

OpenStudy (anonymous):

but every coordinate on the unit circle has either a sin and cos.. just clarifying :D

hartnn (hartnn):

yes, that is true!

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