Mathematics
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OpenStudy (anonymous):
suppose angle B=60 degrees, and length of b=2
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OpenStudy (anonymous):
hartnn (hartnn):
what have you tried? :)
OpenStudy (anonymous):
angle a is 30 degrees
OpenStudy (anonymous):
which means b is 60 degrees
hartnn (hartnn):
A=30 is correct,
B = 60 is given,
go on
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OpenStudy (anonymous):
tan30=a/2
OpenStudy (anonymous):
2*tan(30)=a/2
hartnn (hartnn):
a =2 tan 30
OpenStudy (anonymous):
which is 1.15 which is just 1
OpenStudy (anonymous):
they want the exact measures
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hartnn (hartnn):
since we are not allowed decimals,
whats tan 30 in fraction ?
OpenStudy (anonymous):
1/sqrt3
hartnn (hartnn):
or
lets try to get 'c' first using sin B
hartnn (hartnn):
ok,
thats correct, so a = 2/\sqrt 3
hartnn (hartnn):
\(a= \dfrac{2}{\sqrt 3 }\)
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OpenStudy (anonymous):
so sin60=2/c, 2*sin60,
OpenStudy (anonymous):
sin of 60 degrees is sort(3)/2
OpenStudy (anonymous):
sqrt*
hartnn (hartnn):
yes
sqrt 3/2 = 2/c
so c = 2*2/ sqrt 3 = ...
OpenStudy (anonymous):
4/sqrt(3)
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hartnn (hartnn):
\(\huge \checkmark \)
OpenStudy (anonymous):
so basically we are transforming the degrees into the coordinates of either sin or cos .. i'm slow :)
hartnn (hartnn):
i didn't get that :P
we are trying to find the missing angles and sides of a triangles using sin/cos/tan ....
OpenStudy (anonymous):
but every coordinate on the unit circle has either a sin and cos.. just clarifying :D
hartnn (hartnn):
yes, that is true!