write an equation of each line
\[slope=\frac{ 3 }{ 5} ; through (-4,0)\]
Point slope form \[\Large y-y_1 = m\left(x-x_1\right)\] Plug in the given slope \[\Large y-y_1 = \frac{3}{5}\left(x-x_1\right)\] and the given point \[\Large y-0 = \frac{3}{5}\left(x-(-4)\right)\] from here solve for y
Try to get the equation into the form `y=mx+b`
m= -5/5=(-4,0) y=5/ ?????
you agree that `x-(-4)` turns into `x+4` right?
yes
and the `y-0` is simply `y`
So, \[\Large y-0 = \frac{3}{5}\left(x-(-4)\right)\] \[\Large y = \frac{3}{5}\left(x+4\right)\] \[\Large y = \frac{3}{5}x+\frac{3}{5}*4 \ \ ... \ \text{distribute}\] \[\Large y = \frac{3}{5}x+\frac{3}{5}*\frac{4}{1}\] \[\Large y = \frac{3}{5}x+\frac{3*4}{5*1}\] \[\Large y = \frac{3}{5}x+\frac{12}{5}\]
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