Question

With 4.95 g of baking soda, how many moles of NaOH should be formed?
Using stoichiometric calculations
Reaction 1: 1 NaHCO3(s) → 1 NaOH(s) + 1 CO2(g)

Answer 1

1. Convert the mass to moles

2. write a ratio of the chemical compounds of interest and their respective stoichiometric coefficients

\(\sf \dfrac{moles~of~baking~soda}{baking~soda's~coefficient}=\dfrac{moles~of~NaOH}{NaOH's~coefficient}\)

3. solve for moles of NaOH

use \(\sf moles=\dfrac{mass}{molar~mass}\) for 1. and 3.

Answer 2

would it look like this, .0589/1=.123759/1

Answer 3

yes it would.

for this example the ratio doesn't really matter because both coefficients are equal to 1, but this is how you solve all stoichiometry problems.

Answer 4

wait, no, where did you get 0.123579?

Answer 5

moles of NaOH should be your unknown variable in the ratio, what you are solving for.

Answer 6

.0589/1=?/1
.0589=?/1
How do I solve this because I keep on getting the wrong answer which is .0589

Answer 7

it should be that, 0.058923 moles