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Chemistry 16 Online
OpenStudy (anonymous):

If the following elements were to form ions, they would attain the same number of electrons as which noble gas? elements: Be, Ca, Al, Rb, Se, F, P noble gas: He, Ne, Ar, Kr

OpenStudy (photon336):

You need to first identify what group those elements are in first Beryllium and calcium are both in group 2. they are metals so they are going to lose 2 electrons. Calcium has 20 electrons and 20 protons, if it loses 2 electrons it's configuration resembles Argon. Beryllium has 4 protons and 4 electrons. if it loses 2 electrons it has 2 electrons now and this configuration resembles helium.

OpenStudy (photon336):

@claudia_lcl

OpenStudy (photon336):

Try fluorine and tell me what noble gas it would represent

OpenStudy (anonymous):

Fluorine has 9 protons and 9 electrons?

OpenStudy (photon336):

yes

OpenStudy (photon336):

does it want to gain electrons or lose them?

OpenStudy (anonymous):

Does that mean it's going gain 1 electron

OpenStudy (photon336):

yes exactly, how do you know?

OpenStudy (anonymous):

because fluorine is not an ion, so it usually gain electrons, and also it's on the right side of the periodic table

OpenStudy (photon336):

yes, fluorine has a tendency to gain an electron because of it's position on the periodic table, and because of it's high electronegativity

OpenStudy (anonymous):

But i still do not understand which noble gas does it represent. Isn't there is no charges for noble gas?

OpenStudy (photon336):

@claudia_lcl so that's right noble gases don't have charges, but an electron configuration can be similar to the noble gases. if fluorine gains say one electron take a look, what electron configuration does it represent now that it has 10 electrons? HINT: what element has 10 electrons on the periodic table |dw:1444012725958:dw|

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