How do I solve this problem? The volumes of two cylindrical cans of the same shape vary directly as the cubes of their radii. If a can with a six-inch radius holds 1½ pints, how many gallons will a similar can with a 24-inch radius hold?
how many pints is a gallon
I don't know, I'll have to google it.
okay do that
now the volumes of these 2 objects vary as a function of the cubes of their radii
8
lets suppose Volume of Can A = k*r^3 volume of can B = k*R^3 where R= 24 and r=6 we want to see how many of Can A fit in can B so we know hoiw many pints or gallons go in there
Oh, I just feel so stressed and it makes difficult for me to comprehend.
okay dont worry we will take this slow
So, what's the very first step in this problem?
How do I solve this problem? The volumes of two cylindrical cans of the same shape vary directly as the cubes of their radii.
The volumes of two cylindrical cans of the same shape vary directly as the cubes of their radii.
read this sentence
It says you've been typing for a while. Is that an error?
let Vol_A be the volume of can with radius r = 6 inches Vol_A=k*r^3 Vol_A is varying with respect to r^3 so some constant k times r^3
Is there a significance to your typing of the _ symbol?
no =.= its just a label for the variable
let Vol_B be the volume of can with radius R=24 inches Vol_B=k*R^3 Vol_B is varying with respect to R^3 so some constant k(notice same constant) times R^3
now what we want to know is how many times bigger volume B is than volume A
then we will know how many of Vol_A will fit in volume_B
|dw:1444022480876:dw|
Join our real-time social learning platform and learn together with your friends!