A ball is thrown from a height of
32
meters with an initial downward velocity of
2/ms
. The ball's height
h
(in meters) after
t
seconds is given by the following.
=h−32−2t5t^2
How long after the ball is thrown does it hit the ground?
Round your answer(s) to the nearest hundredth.

Question

A ball is thrown from a height of 
32
 meters with an initial downward velocity of 
2/ms
. The ball's height 
h
 (in meters) after 
t
 seconds is given by the following.
=h−32−2t5t^2
How long after the ball is thrown does it hit the ground?
Round your answer(s) to the nearest hundredth.

zpupster · Answer

0=−32−2t+5t2 when the ball hits the ground h=0
5t2 -2t - 32 = 0  rearranging solve this with quadratic formula
$$-b \pm \frac{ \sqrt { b^2-4ac} }{ 2a }$$

zpupster · Answer

take the negative answer becasue the balls traveling in a downward direction.

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