Question

Will Medal Answer ASAP!!!!!


1: What is the GCF of the numerator and denominator in the following fraction? 21m^2n/28mn^2


7m^2n^2
7mn
21m^3n^3
mn

Answer 1

so whats the question?

Answer 2

im putting it up right now!

Answer 3

alrighty then.

Answer 4

@paki

Answer 5

@geny55 @Photon336

Answer 6

So this is what we have right @jessie13

\[\frac{ 21m ^{2}n }{ 28mn ^{2} }\]

Answer 7

so greatest common factor, is the largest number that can go into both the numerator and denominator

Answer 8

1 dont get it!

Answer 9

Let's break this up into two parts

Answer 10

\[\frac{ 21 }{ 28 } * (\frac{ m ^{2}n }{ mn ^{2} })\]

Answer 11

do you know how to subtract powers?

Answer 12

whenever we divide exponents we subtract the exponents. so we will do that first

\[\frac{ m ^{2}n}{ mn ^{2} } = Numerator[ m ^{2}-m ^{1} = m] denominator [n ^{1}-n ^{2}] = n ^{-1}\]

we simplify the variables first.

\[\frac{ m }{ n }\]

Answer 13

@jessie13 so now this is what we have

we need to find the greatest common factor so it has to be the largest number that goes into both 21 and 28

\[\frac{ 21 }{ 28 } *(\frac{ m }{ n })\]

Answer 14

wait the gcf is 7

Answer 15

@jessie13 yep :) here's why. and that's why I told you to do it that way

yeah so