Question

Will medal...

2x-9/x^2- x- 6 = A/x-3 + B/x+2
/ as in fraction and ^2 as squared

Answer 1

HI!!

Answer 2

partial fractions?

Answer 3

Mhm.

Answer 4

@ganeshie8

Answer 5

Hello.?

Answer 6

Ganeshie8, can you help?

Answer 7

you may use the cover up method
http://www.math-cs.gordon.edu/courses/ma225/handouts/heavyside.pdf

Answer 8

\[\dfrac{2x-9}{x^2- x- 6} = \dfrac{A}{x-3} + \dfrac{B}{x+2} \]

\[\dfrac{2x-9}{(x-3)(x+2)} = \dfrac{A}{x-3} + \dfrac{B}{x+2} \]

Answer 9

Look at the "left hand side" expression.
Cover up \(x-3\) and plugin \(x=3\), what do you get ?

Answer 10

\[\dfrac{2x-9}{(x+2)} \]

plugin x=3 above

Answer 11

2(3)-9/5

Answer 12

So, 1 / 5?

Answer 13

(2(3)-9)/5

(6-9)/5

= ?

Answer 14

1/5
and
-3/5

Answer 15

what 1/5 ?

Answer 16

Wait sorry.

Answer 17

i get -3/5 on both

Answer 18

Lets work it step by step, shall we ?

so far we have \(A=-\dfrac{3}{5}\)

Answer 19

Yes.

Answer 20

Next, cover up \(x+2\) and plugin \(x=-2\) in :


\[\dfrac{2x-9}{(x-3)} \]

Answer 21

13/5?

Answer 22

Yep!
you may double check with wolfram
http://www.wolframalpha.com/input/?i=partial+fractions+%282x-9%29%2F%28x%5E2-+x-+6%29

Answer 23

Thanks so much!

Answer 24

yw