Question

help me plz

Answer 1

@Directrix

Answer 2

brb in 20

Answer 3

im back

Answer 4

first of all you should know is it horizontal or vertical
a always greater than b `a>b`
if a is under the x variable then it would be `horizontal equation`
\[\rm \frac{ (x-h)^2 }{\color{ReD}{ a^2} }+ \frac{ (y-k)^2 }{ b^2 }=1\]
if a is under the y variable then it would be `vertical equation`
\[\rm \frac{ (x-h)^2 }{ b^2 }+ \frac{ (y-k)^2 }{\color{reD}{ a^2} }=1\]

Answer 5

so is it vertical or horizontal ?

Answer 6

i think its vertical

Answer 7

foci for horizontal \[\large\rm (h, k \pm c)\]
and for vertical equation \[\large\rm (h \pm c , k)\]
use the equation to find c \[\huge\rm c^2 =a^2-b^2\]

Answer 8

ok so which one do i use

Answer 9

well a is bigger number which is under the x variable so is it vertical or horizontal ?

Answer 10

read my first comment :=)

Answer 11

so it is horizontal right

Answer 12

yes right \[\huge\rm \frac{ x^2 }{ \color{ReD}{36} } +\frac{ y^2 }{ 11 }=1\] now use the equation posted above to find c

Answer 13

c^2=a^2-b^2 this one

Answer 14

wait what

Answer 15

foci for horizontal \[\large\rm (h, k \pm c)\]
and for vertical equation \[\large\rm (h \pm c , k)\]
those two are foci pair
we need
so
use this equation to find c \[\huge\rm c^2 =a^2-b^2\]

Answer 16

a^2 and b^2 are in the given equation

Answer 17

wow ok so umm can you start me off plz

Answer 18

`horizontal equation` for ellipse
\[\rm \frac{ (x-h)^2 }{\color{ReD}{ a^2} }+ \frac{ (y-k)^2 }{ b^2 }=1\]
the number at the denominator are a^2 and b^2
and like i said bigger number equal to a^2

Answer 19

what two numbers are replaced with a^2 and b^2 in this equation \[\huge\rm \frac{ x^2 }{ \color{ReD}{36} } +\frac{ y^2 }{ 11 }=1\] ??

Answer 20

brb i gtg cook dinner

Answer 21

36 and 11

Answer 22

right which one is a^2 and which one is b^2 ?

Answer 23

a^2 is 36 b^2 is 11

Answer 24

@IrishBoy123

Answer 25

{ (x-h)^2 }{36} }+/{ (y-k)^2 }{11}=1 is this the correct formula

Answer 26

this ellipse is centred on the origin

yep?

Answer 27

yep

Answer 28

yep

Answer 29

Para-phrasing Wiki:

The distance from the origin O to either focus is f where:

\[f = \sqrt{a^2-b^2}.\]

Answer 30

ok she gave me a diffrent formula soo what do i do im so confused now

Answer 31

here, what is a and what is b?

general equation for ellipse centred on Origin is:
\(\large \frac{{x}^2}{{a}^2} + \frac{{y}^2}{{b}^2} = 1\)

Answer 32

a = ??

b = ??

Answer 33

then

Answer 34

(x-h)^2 }{36} }+/{ (y-k)^2 }{11}= ok so i got this

Answer 35

so that means you have finished it?!

Answer 36

no i have not thats the first equation

Answer 37

(y-k)^2 {11} this is my answer

Answer 38

OK

for an equation centred on O, we have general equation:
\[\large \frac{{x}^2}{{a}^2} + \frac{{y}^2}{{b}^2} = 1\]

The focii are at a distance f from O, where
\[f = \sqrt{a^2-b^2}\]