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Mathematics 10 Online
OpenStudy (anonymous):

How to factor 10x2-80 Pls list steps

OpenStudy (anonymous):

\[10x^{2} - 80\]

OpenStudy (anonymous):

well do you know what 10^2 is

OpenStudy (anonymous):

well its 10 x 10 = 100

OpenStudy (anonymous):

100

OpenStudy (anonymous):

Yea lol

OpenStudy (anonymous):

so now the problem is 100 - 80

OpenStudy (anonymous):

but thats not factoring

OpenStudy (anonymous):

ok it's 20.

OpenStudy (anonymous):

ohh

OpenStudy (anonymous):

https://www.symbolab.com/solver/algebra-calculator/10%5E%7B2%7D-80/?origin=button this may help if not im sorry

OpenStudy (anonymous):

Its 10(x^2-8)

OpenStudy (anonymous):

Its alright :) thanks

OpenStudy (anonymous):

ok i can help with that if you still need help

OpenStudy (anonymous):

let me give some a try, give me a min

OpenStudy (anonymous):

@chinadayyy 16x^2-4

OpenStudy (anonymous):

ok is this factoring again?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

@haleyelizabeth2017

OpenStudy (happy_to_help):

\[16(x^{2}-4)\] Step one:Use distributive property 16 times x to the power of 2=16x^2 16 times 4=64 16x^2-64

OpenStudy (anonymous):

Eli

OpenStudy (anonymous):

So for 16x^2-4 I got (4x-2) (4x+2)

OpenStudy (haleyelizabeth2017):

That is one way to do it

OpenStudy (haleyelizabeth2017):

But, that's not the simplest form.

OpenStudy (anonymous):

for 4x^2-25 i got (2x-5) (2x+5)

OpenStudy (anonymous):

It isn't?

OpenStudy (haleyelizabeth2017):

Yes :)

OpenStudy (haleyelizabeth2017):

and no

OpenStudy (anonymous):

Explain ? pls :)

OpenStudy (haleyelizabeth2017):

For \(16x^2-4\) the simplest form would be 4(2x-1)(2x+1)

OpenStudy (haleyelizabeth2017):

because you would get \(4(4x^2-1)\) which \(4x^2-1\) turns into (2x-1)(2x+1)

OpenStudy (haleyelizabeth2017):

So, then you move the four back and get 4(2x-1)(2x+1)

OpenStudy (anonymous):

OHH I see it..

OpenStudy (haleyelizabeth2017):

:)

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