Mathematics
10 Online
OpenStudy (anonymous):
How to factor 10x2-80
Pls list steps
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OpenStudy (anonymous):
\[10x^{2} - 80\]
OpenStudy (anonymous):
well do you know what 10^2 is
OpenStudy (anonymous):
well its 10 x 10 = 100
OpenStudy (anonymous):
100
OpenStudy (anonymous):
Yea lol
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OpenStudy (anonymous):
so now the problem is 100 - 80
OpenStudy (anonymous):
but thats not factoring
OpenStudy (anonymous):
ok it's 20.
OpenStudy (anonymous):
ohh
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OpenStudy (anonymous):
Its 10(x^2-8)
OpenStudy (anonymous):
Its alright :) thanks
OpenStudy (anonymous):
ok i can help with that if you still need help
OpenStudy (anonymous):
let me give some a try, give me a min
OpenStudy (anonymous):
@chinadayyy 16x^2-4
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OpenStudy (anonymous):
ok is this factoring again?
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
@haleyelizabeth2017
OpenStudy (happy_to_help):
\[16(x^{2}-4)\]
Step one:Use distributive property
16 times x to the power of 2=16x^2
16 times 4=64
16x^2-64
OpenStudy (anonymous):
Eli
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OpenStudy (anonymous):
So for 16x^2-4 I got (4x-2) (4x+2)
OpenStudy (haleyelizabeth2017):
That is one way to do it
OpenStudy (haleyelizabeth2017):
But, that's not the simplest form.
OpenStudy (anonymous):
for 4x^2-25 i got (2x-5) (2x+5)
OpenStudy (anonymous):
It isn't?
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OpenStudy (haleyelizabeth2017):
Yes :)
OpenStudy (haleyelizabeth2017):
and no
OpenStudy (anonymous):
Explain ? pls :)
OpenStudy (haleyelizabeth2017):
For \(16x^2-4\) the simplest form would be 4(2x-1)(2x+1)
OpenStudy (haleyelizabeth2017):
because you would get \(4(4x^2-1)\) which \(4x^2-1\) turns into (2x-1)(2x+1)
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OpenStudy (haleyelizabeth2017):
So, then you move the four back and get 4(2x-1)(2x+1)
OpenStudy (anonymous):
OHH I see it..
OpenStudy (haleyelizabeth2017):
:)