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Find the sum of a finite geometric sequence from n = 1 to n = 6, using the expression −2(5)n − 1
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@hwyl can you help?
\[\sum_{n=1}^6-2(5)^{n-1}\]?
i mean is that the question?
i think so.. i don't remember how to do this
pull the minus two out first, deal with it at the end
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\[\sum_{n=1}^6-2(5)^{n-1}=-2\sum_{n=1}^6(5)^{n-1}\]
then \[\sum_{n=1}^6(5)^{n-1}=\frac{5^6-1}{5-1}\] compute that, multiply the restult by \(-2\)
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