Question

State the missing factor
4n^2+8n-60=(?)(n+5)

Answer 1

what times \(n\) is \(4n^2\)?

Answer 2

4n?

Answer 3

yes

Answer 4

and what times \(5\) gives \(-60\)?

Answer 5

-12

Answer 6

ok put them together are you are done

Answer 7

(4n-12)

Answer 8

yup

Answer 9

at the back of my textbook the answer is 4(n-3)

Answer 10

not really factored completely that would be \[4(n-3)(n+5)\]

Answer 11

yeah because the terms of \(4n-12\) have a common factor of 4

Answer 12

so you divide (4n-12) by 4 to get 4(n-3) ?

Answer 13

that is not "division" that is factoring, aka the distributive property \[4\times x-4\times 3=4(x-3)\]

Answer 14

ohh okay