Ask your own question, for FREE!
Chemistry 7 Online
OpenStudy (anonymous):

Will fan and medal!! Give the oxidation number of Nitrogen in each of the following compounds or ions: a) N2O b)Ca(NO3)2 c)NH4 ^+ d)N2H4 e)Mg3N2 Please explain how you got them

OpenStudy (photon336):

Let's take c) first 1. first we look to see if there's any kind of charge on the molecule 2. then we look for the oxidation states of the element(s) 3. we multiply oxidation state by the number of atoms for that element 4. add them all up. so for \[NH_{4}^{+}\] We have 1 atom of nitrogen and 4 atoms of hydrogen. Hydrogen has an oxidation state of +1 and there are four atoms right? so that's +4 we realize that the charge on our compound is +1 so the oxidation states must sum up to +1. Now we have +4 for hydrogen, and what oxidation state for nitrogen will give us +1 total. that's -3. so nitrogen is -3 and hydrogen is +1 -3 + 4 = +1 try choice D and tell me what you get

OpenStudy (photon336):

\[N_{2}H_{4} \] try this one it's one of the choices @Shaekitchen

OpenStudy (anonymous):

im thinking aboout it but im getting no where just give me a min @Photon336

OpenStudy (anonymous):

Im sorry im still not quite understanding @Photon336 Im nnot sure how I find what they add up to

OpenStudy (photon336):

@Shaekitchen first step is there a charge on N2H4 ?

OpenStudy (anonymous):

How do i tell like i know that H has 1+ and theres 4 of them so 4+ right? @Photon336

OpenStudy (photon336):

yes correct

OpenStudy (photon336):

@shaekitchen read these rules below. these are the most important YOU MUST LOOK TO SEE IF THERE IS A CHARGE ON THE MOLECULE, as in an ion. IF THERE IS A CHARGE: The oxidation states must add up to that charge. IF THERE IS NO CHARGE: the sum of the oxidation states = zero.

OpenStudy (anonymous):

so in N2H4 theres no charge correct?? @Photon336

OpenStudy (photon336):

:) yep

OpenStudy (anonymous):

sso then would the charge on N be 2+ ?

OpenStudy (photon336):

@Shaekitchen work out the entire problem and show me step by step.

OpenStudy (photon336):

this will help you understand this

OpenStudy (photon336):

@Shaekitchen

OpenStudy (anonymous):

I think i got it -6?

OpenStudy (anonymous):

@Photon336 thats the only way i got it to cancel it out

OpenStudy (photon336):

|dw:1444101389055:dw|

OpenStudy (photon336):

|dw:1444101598809:dw|

OpenStudy (photon336):

@Shaekitchen please take a close look at how i set up the problem

OpenStudy (anonymous):

okay I am going to try N2O Thaat way you explained i really helped! @Photon336

OpenStudy (photon336):

@Shaekitchen Write out everything by using the drawing tool then post it here

OpenStudy (photon336):

But you need to make sure that you understand how I did it, does tat make sense?

OpenStudy (anonymous):

My computer isnt letting me use the drawing tool If i have N2O I have a charge on O of -2 right? Theres so many charges on O how do I know which one to use? @Photon336

OpenStudy (photon336):

You always ask this question first before doing anything @Shaekitchen is there a charge on the molecule? oxygen almost always has a charge of -2

OpenStudy (anonymous):

Theres no charge on this molecule but if O is 2- doesnt that mean that N would just be 1-?

OpenStudy (photon336):

almost, but no charge means oxidation states MUST = ZERO ask your self if you summed up those numbers would you get zero?

OpenStudy (anonymous):

I got it it would be +1 Im going to do the rest on my own as my computer is slow thank you for your help @Photon336

OpenStudy (photon336):

@Shaekitchen great job, it's +1 remember to use those rules. you should be able to figure out the rest now take care

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!