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@Directrix
The object is to eliminate one of the three variables and reduce the system of equations to a 2 by 2 system. After that, the next task is to eliminate one of the remaining two variables.
OK
(1) x + y + z = -5 (2) x - y + 3z = -1 (3) 4x + y + z = -2
In equations 1 and 2, add the two equations. The y variables will add to 0. x + y + z = -5 x - y + 3z = -1 ----------------- 2x + 4z = -6 --->**
In equations 2 and 3, add the two equations. The y variables there will also add to 0. (2) x - y + 3z = -1 (3) 4x + y + z = -2 ----------------------- 5x + 4z = -3---> **
The variable y has been eliminated. Look back at the work and see if you understand how that was done.
OHHH
The 3 by 3 system has been transformed to a 2 by 2 system: 2x + 4z = -6 --->** 5x + 4z = -3---> **
Look at the z variables. They are both +4z. To eliminate the z variables, multiply each member of one of the two equations by (-1).
MAKES SINCE SO FAR
2x + 4z = -6 ---> Mult by -1 -2x -4z = 6 5x + 4z = -3---> 5x + 4z = -3 --------------- 3x = 3 x = 1
X has been found. Now, we have to find y and z.
OHHH
Using one of the 2 variable equations, substitute 1 in for x and solve for y. 2x + 4z = -6 2*1 + 4z = -6 2 + 4z = -6 -2 -2 --------------- 4z = -8 z = -2
So, x = 1 and z = -2 Go to one of the 3 by 3 equations and substitute in for x and z. Then, you can find y.
WOW I THOUGHT IT WAS LESS THEN THISS HAHA
I chose the first one. (1) x + y + z = -5 1 + y -2 = -5 y -1 = -5 y = -5 + 1 y = -4 (1, -4, -2) You should copy this so that you will have an example to use in similar problems.
HEY IM FIXEN TO GO TO BED WE WILL FINISH THIS TOMORROW PLZ
Also, check out this 3 by 3 online solver. http://math.bd.psu.edu/~jpp4/finitemath/3x3solver.html
OK I WILL
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