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OpenStudy (anonymous):
@Michele_Laino
OpenStudy (michele_laino):
again we have to consider two cases, so we have to solve the subsequent two systems:
\[\begin{gathered}
\left\{ \begin{gathered}
x \geqslant 0 \hfill \\
x < 6 \hfill \\
\end{gathered} \right. \hfill \\
\hfill \\
\left\{ \begin{gathered}
x < 0 \hfill \\
- x < 6 \hfill \\
\end{gathered} \right. \hfill \\
\end{gathered} \]
OpenStudy (anonymous):
{x|x> -6 and x< 6} ?
OpenStudy (michele_laino):
correct! the solution is:
\[\left\{ {x \in \mathbb{R}| - 6 < x < 6} \right\}\]
OpenStudy (anonymous):
so |x| < 5 is
{x|x < -5 or x > 5}
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OpenStudy (michele_laino):
more precisely is:
\[\left\{ {x \in \mathbb{R}| - 5 < x < 5} \right\}\]
OpenStudy (anonymous):
ok i still a little confused...
OpenStudy (michele_laino):
|dw:1444148224816:dw|
OpenStudy (michele_laino):
the solution intervals, geometrically speaking, is given by all points between x=-5 and x=5, the ends x=-5 and x=5 are not included
OpenStudy (michele_laino):
interval*
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