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Mathematics 8 Online
OpenStudy (anonymous):

|x|<6

OpenStudy (anonymous):

@Michele_Laino

OpenStudy (michele_laino):

again we have to consider two cases, so we have to solve the subsequent two systems: \[\begin{gathered} \left\{ \begin{gathered} x \geqslant 0 \hfill \\ x < 6 \hfill \\ \end{gathered} \right. \hfill \\ \hfill \\ \left\{ \begin{gathered} x < 0 \hfill \\ - x < 6 \hfill \\ \end{gathered} \right. \hfill \\ \end{gathered} \]

OpenStudy (anonymous):

{x|x> -6 and x< 6} ?

OpenStudy (michele_laino):

correct! the solution is: \[\left\{ {x \in \mathbb{R}| - 6 < x < 6} \right\}\]

OpenStudy (anonymous):

so |x| < 5 is {x|x < -5 or x > 5}

OpenStudy (michele_laino):

more precisely is: \[\left\{ {x \in \mathbb{R}| - 5 < x < 5} \right\}\]

OpenStudy (anonymous):

ok i still a little confused...

OpenStudy (michele_laino):

|dw:1444148224816:dw|

OpenStudy (michele_laino):

the solution intervals, geometrically speaking, is given by all points between x=-5 and x=5, the ends x=-5 and x=5 are not included

OpenStudy (michele_laino):

interval*

OpenStudy (michele_laino):

|dw:1444148385611:dw|

OpenStudy (anonymous):

ok i think i got it thankyou

OpenStudy (michele_laino):

:)

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