Question

Help with a study guide question, i will give best response. (Attached file.) Please Help me! I'm study for a big test

Answer 1

apply distributive property where possible
distributive property says a(b+c) is equal to ab+ac
I see you have 3(x-y)
apply distributive property there

Answer 2

you can tell me what you get when you apply distributive property to 3(x-y)?

Answer 3

3xy? or 3(y-x) p
Idk how to do the distributive property

Answer 4

you do see distributive property is a(b+c)=ab+ac
we are taking the outer number and multiplying it to both terms inside the ( )?

Answer 5

example
6(2+7) is the same as 6*2+6*7
though we didn't need distributive property here because we know what 2+7 is...
6(2+7)=6(9)=54
but we see we get the same number using the distributive property
6(2+7)=6*2+6*7=12+42=54

Answer 6

here we can't do y take away x because we don't know what x and y are
so you have to apply distributive property here where you have 3(x-y)

Answer 7

3(x-y) is the same as 3x-3y

Answer 8

\[3x+4y+3(x-y)-4x \\ 3x+4y+3x-3y-4x\]

Answer 9

now using that addition is commutative to place like terms together

Answer 10

commutative property is just changing the order

Answer 11

so for the first slot it's written like 3x+4y+3x-3y-4y = Distributive property??

Answer 12

almost

Answer 13

you want to leave that last term as it was
we didn't do anything to it

Answer 14

Umm, how do you write exactly?
I'm a little lost on what your saying...sorry

Answer 15

should be 3x+4y+3x-3y-4x by use of the distributive property

Answer 16

-4x doesn't just turn into -4y

Answer 17

Oh! I got it! Okay give me a sec to write it, and then we can move to the next slot?

Answer 18

I got it! so next one?

Answer 19

have you tried changing the order to put like terms together yet? that was what I suggested above.... I also gave the name of this property too. :)
You try it and I will check it.

Answer 20

Wait, what do you want me to do?

Answer 21

change the order so like terms are together

Answer 22

like terms are terms with the same variable part

Answer 23

you should see three terms that have the common variable x
you should see two terms that have the common variable y

Answer 24

put all your x terms together and put all your y terms together

Answer 25

10x +7y
Like that?

Answer 26

@freckles

Answer 27

like if I had a+a+b+a+b-4a
reorder so that like terms are together
a+a+a-4a+b+b

Answer 28

3x+3x+4x=10x
4y+3y=7

Answer 29

^^ That?

Answer 30

you shouldn't change the sign in front of the term
you had
3x+4y+3x-3y-4x

by commuative property we can write this as
3x+3x-4x+4y-3y

Answer 31

Oh... I was supposed to add all the X's in order, and all the y's after that?

Answer 32

Example:
\[a+a+b+a+4(\frac{1}{4}b-a) \text{ given } \\ a+a+b+a+4 \cdot \frac{1}{4} b-4a \text{ by distributive property } \\ a+a+b+a+b-4a \text{ by simplification } \\ a+a+a-4a+b+b \text{ by commutative property } \\ (a+a+a-4a)+(b+b) \text{ by associative property } \\ a(1+1+1-4)+b(1+1) \text{ by distributive property } \\ a(-1)+b(2) \text{ by simplification } \\ -a+2b \text{ by commautive property }\]

Answer 33

anyways I be back
I have thing

Answer 34

Wait you're leaving?! I thought you'd help me finish the problem??

Answer 35

@freckles COME BACK!!!!!

Answer 36

Math tease.

Answer 37

Sorry. I had something come up.
Anyways I hoped the example helped.