Question

Find the first, fourth, and eighth terms of the sequence. A(n)=-5*2^n^-1

–5; –40; –640
–20; –160; –2,560
–10; –80; –1,280
1; –1,000; –10,000,000

Answer 1

@Mehek14 can please u help?

Answer 2

@Loser66 can u help?

Answer 3

@jim_thompson5910

Answer 4

@hartnn can u please help?

Answer 5

\[A(n)=5\times 2^{n-1}\]

Is that how the equation is showing?

Answer 6

yes!

Answer 7

So first term you would sub in n=1
\[A(n)= -5 \times 2^{n-1}\]
\[A(1)= -5 \times 2^{1-1}\]
\[A(1)= -5 \times 2^{0}\]
\[A= -5 \times 1\]
A=-5

Answer 8

fourth sub in n=4
\[A= -5 \times 2^{4-1}\]
\[A= -5 \times 2^{3}\]
\[A= -5 \times 8\]
A=-40

Answer 9

try the eight term and see if you find the matching sequence from the answers :)

Answer 10

-640

Answer 11

Thank You so much. Could you help me with this one?
Evaluate the function rule for the given value.
f(x)=15^x for x=3

Answer 12

15^3=3375

Answer 13

yes that looks good