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Chemistry 16 Online
OpenStudy (anonymous):

If four moles of a gas at a pressure of 5.4 atmospheres have a volume of 120 Liters What is the Temperature?

OpenStudy (anonymous):

|dw:1444169877346:dw| Is that how you set it up?

OpenStudy (photon336):

yes you are correct but make sure you re-arrange the formula FIRST and then put in the numbers. Start with this formula \[pV = nRT\] ask your self what are we looking for? Temperature. so we solve for T \[\frac{ pV }{ nR } = T\] \[\frac{ 5.4atm*120L }{ 4.0mol*0.082mol ^{-1} L,atm, K ^{-1}} = T, \in kelvins\]

OpenStudy (photon336):

@Gir_16

OpenStudy (anonymous):

ok

OpenStudy (photon336):

does this make sense to you @Gir_16 ?

OpenStudy (anonymous):

kinda but the part near the end were it says l atm k.. would I multiply those? and bye what??

OpenStudy (anonymous):

@Photon336

OpenStudy (photon336):

@Gir_16 those are just units, all you would have to do is divide (5.4*120)/(4*0.82) the units are just to show you that they cancel out and you're left with Temperature. let me show you

OpenStudy (anonymous):

ok

OpenStudy (photon336):

|dw:1444171210243:dw|

OpenStudy (anonymous):

ok

OpenStudy (photon336):

@Gir_16 as you can see all the units cancel out and we're left with temperature that's what we must find

OpenStudy (anonymous):

ok

OpenStudy (photon336):

just remember to always solve for the variable you're looking for FIRST then put in the numbers.

OpenStudy (anonymous):

kk tanks

OpenStudy (photon336):

np take care

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