Question

factoring quadratic expression...

Answer 1

\[\huge 294a^2 - 54 \]

Answer 2

@Nnesha

Answer 3

@jim_thompson5910 @hartnn @Jhannybean

Answer 4

\[\large 294a^2 - 0a - 54\]

Answer 5

larget common factor of \(294\) and \(24\) is?

Answer 6

get rid of that stupid zero

Answer 7

okay sorry

Answer 8

don't you mean the gcf of 294 and 54 ?

Answer 9

yes
i get 6

Answer 10

Hahahaha

Answer 11

so start with \[6(49a^2-9)\] then factor \[49a^2-9\] as the difference of two squares

Answer 12

\[a^2-b^2 = (a-b)(a+b)\]

Answer 13

(7a + 3)(7a - 3)

Answer 14

or rather,.... \(ca^2-b^2 = (ca-b)(ca+b)\) :') \(c\) is the coefficient of one of the terms lol

Answer 15

\[\heartsuit^2-\spadesuit^2=(\heartsuit+\spadesuit)(\heartsuit -\spadesuit)\][

Answer 16

Oh you think you're fancy huh

Answer 17

just showing off

Answer 18

lol

Answer 19

\[\xi^2 -\omega^2=(\xi+\omega)(\xi-\omega)\]

Answer 20

You are correct @calculusxy , just don't forget to multiply by the 6

Answer 21

can i make sure the answer to another question?

Answer 22

\[\large 12x^2 + 12x + 3\]
\[\huge Answer \]
\[\large 3(2x+1)(2x+1)\]

Answer 23

looks good to me
you @Jhannybean ?

Answer 24

well i did the same question, but in a different way and got a different answer ( can u catch my mistake)
12x^2 + 12x + 3
12x^2 + 6x + 6x + 3
2x(2x+3) 3(2x + 3)
(2x - 3)(2x + 3)

Answer 25

\[\begin{align}12x^2+12x+3 &\rightarrow 4x^2+4x+1 \\&\rightarrow x^2+4x+4 \\&\rightarrow (x+2)(x+2) \\&\rightarrow \left(x+\frac{2}{4}\right)\left(x+\frac{2}{4}\right) \\&\rightarrow \left(x+\frac{1}{2}\right)\left(x+\frac{1}{2}\right) \\&\rightarrow \color{red}{(2x+1)(2x+1)}\end{align} \]

Answer 26

For this method i simplify the quadratic by putting it in standard form \(ax^2+bx+c\) typically where \(a=1\)

find the factors

divide the factors by the leading coefficient we used to simplify our equation

If the simplification of the factors does not give you an integer value but a fractional one, multiply the variable with the denominator of the fraction.

You'll have your factorization

Answer 27

if there is a GCF better to take it out