Question

exponents...

Answer 1

\[\huge \frac{ (x^4y^{-2})^{-3} }{ 2x^{-2}y^2x^4 }\]

Answer 2

Answer:
\[\large \frac{ y^{14} }{ 2x^{14} }\]

Answer 3

@Jhannybean

Answer 4

some mistake here

Answer 5

\[(x^4y^{-2})^{-3} \iff \frac{1}{(x^4y^{-3})^3}\]

Answer 6

sorry \y^4/2x^{14}

Answer 7

\[\dfrac{\dfrac{1}{(x^4y^{-3})^3}}{2x^{-2}y^2x^4}\]

Answer 8

\[\frac{ y^4 }{ 2x^{14} }\]

Answer 9

Did you need help solving it or just checking to see if it was correct?

Answer 10

checking

Answer 11

alright

Answer 12

\[\dfrac{\dfrac{1}{(x^4y^{-3})^3}}{2x^{-2}y^2x^4} = \dfrac{\dfrac{1}{x^{12}y^{-9}}}{2x^{-2}y^2x^4} =\frac{1}{2x^{12-2+4}y^{-9+2}}=\frac{1}{2x^{14}y^{-7}}=\frac{y^{7}}{2x^{14}} \]

Answer 13

Youve asked a similar question like this before. Hope this method makes sense to you.

Answer 14

here's my way:
\[\frac{ (x^4y^{-2})^{-3} }{ 2x^{-2}y^2x^4 } = \frac{ x^{-12}y^6 }{ 2x^2y^2 } = \frac{ y^4 }{ 2x^{14} }\]

Answer 15

hmm... somehow i miscalculated the \(y\)

Answer 16

trial 2: \[\begin{align}\frac{ (x^4y^{-2})^{-3} }{ 2x^{-2}y^2x^4 } &= \dfrac{\dfrac{1}{\left(\dfrac{x^4}{y^2}\right)^3}}{2x^{-2}y^2x^4} \\&= \dfrac{\dfrac{1}{x^{12}y^{-6}}}{2x^{-2}y^2x^4} \\&=\dfrac{\dfrac{1}{x^{12}y^{-6}}}{2x^{2}y^2} \\ &=\dfrac{1}{(x^{12}y^{-6})(2x^2y^2)} \\&= \frac{1}{x^{12+2}y^{-6+2}} \\&= \color{red}{\frac{y^4}{x^{14}}}\end{align} \]

Answer 17

Sorry Im not that great at simplifying exponents :\

Answer 18

Typo again! I forgot the 2. \[\frac{y^4}{2x^{14}}\]