Question

Find vertical asymptotes of the curve. (Calculus Limits, Question #9)

Answer 1

looks like some webassign business

Answer 2

set the denominator equal to zero and solve

Answer 3

i.e. solve \[x^2-4x=0\]
0 is one answer, there is another

Answer 4

is \[x^2-x^4\] factorable?

Answer 5

oops i made a typo
yes \[x^2-x^4=0\]

Answer 6

it is definitely factorable since both terms have a common factor of \(x^2\)

Answer 7

\[(x+x^2)(x-x^2)\]

Answer 8

\[is (x-x^2) factorable \]

Answer 9

factor out the common factor of \(x^2\)

Answer 10

now whatever you did

Answer 11

*not whatever you did

Answer 12

Ok, I got it. Just had a brain fart. Thanks!

Answer 13

yw
on line class?

Answer 14

Online homework, but class is on school campus

Answer 15

your horizontal asymptote is right, it is \(y=-1\)

Answer 16

Yea, I didn't submit the new answers to the questions yet

Answer 17

I'll be here on openstudy until the next sunrise, still got tons of homework questions left.