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Calculus1
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\[\lim_{x \rightarrow \infty} xe^{-x} \]
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\[e ^{-x}\]
it is the same as \[\lim_{x\to \infty}\frac{x}{e^x}\] does that help?
Well, I got that far. And when I take the limit of that, I would get infinity over infinity. Not sure what to do next.
think what grows faster \(e^x\) or \(x\)
e^x
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of course much much (much) faster
So, since the denominator will be a much bigger number, the fraction will be very small. So is the answer of this limit zero?
yes
Ok, thank you! :)
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