Mathematics
9 Online
OpenStudy (pulsified333):
Assume that n = 13, and p = 3/9.
Find the probability of at least 3 successes and at least 3 failures.
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OpenStudy (pulsified333):
@Musicdude
OpenStudy (anonymous):
ok
OpenStudy (pulsified333):
I've tried two different methods but neither worked
OpenStudy (anonymous):
ok that is a binomial probability within a binomial probability i think. i need to think for this
OpenStudy (anonymous):
hold up i might be wrong
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OpenStudy (pulsified333):
ok
OpenStudy (anonymous):
ok its binomial probability with parameters
OpenStudy (anonymous):
have you seen this yet? or heard of it?
OpenStudy (pulsified333):
I dont think so
OpenStudy (anonymous):
ok its a hard concept so let me see how i can explain it
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OpenStudy (anonymous):
wow im stumped... i cant explain it but do you have a ti-84 or higher?
OpenStudy (anonymous):
i can show you haw to get the answer
OpenStudy (pulsified333):
um I don't because the professor doesn't allow calculators
OpenStudy (anonymous):
O.O
OpenStudy (anonymous):
omg
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OpenStudy (anonymous):
hes evil
OpenStudy (pulsified333):
imagine the test
OpenStudy (anonymous):
im in stat 3 and we use computers
OpenStudy (anonymous):
but we code our own calculations
OpenStudy (anonymous):
ok thats tricky to do without a calculator
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OpenStudy (anonymous):
and i really dont have a pencil because im on my way home on the bus with my phone
OpenStudy (anonymous):
nor paper
OpenStudy (pulsified333):
it's okay
OpenStudy (anonymous):
sorry dude ask @ganeshie8 or @satellite73
OpenStudy (pulsified333):
I got the answer
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OpenStudy (anonymous):
ok cool how?
OpenStudy (pulsified333):
:D
OpenStudy (anonymous):
i just want to see
OpenStudy (anonymous):
lol same
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OpenStudy (pulsified333):
basically do the Bernoulli trials for each one from 3-13 for both and then multiple them together to get .8611
OpenStudy (anonymous):
it would be 2 separate probabilities
OpenStudy (pulsified333):
yeah then multiply them together
OpenStudy (anonymous):
i think it would be two different answers because it is 2 different events
OpenStudy (anonymous):
because both cant exist together
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OpenStudy (pulsified333):
No because it says 3 success "and" 3 failures. Which in Finite math means multiply
OpenStudy (anonymous):
but then where are the 8 trails go? if there aren't success not faliure
OpenStudy (anonymous):
thats the thing
OpenStudy (anonymous):
thats whats tricky because it creates a parameter
OpenStudy (anonymous):
i know the answer but its really complex to get to without a calculator
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OpenStudy (anonymous):
is you did use the Bernoulli trials you would use 3-10 because you have to account for the "at least 3 faliures"
OpenStudy (anonymous):
you there?
OpenStudy (pulsified333):
yeah
OpenStudy (anonymous):
im guessing it would be around .86 just because i know
OpenStudy (anonymous):
and i used a calculator
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OpenStudy (pulsified333):
yeah
OpenStudy (anonymous):
is that around what you got??
OpenStudy (pulsified333):
yeah i got .8611
OpenStudy (anonymous):
yeah thats it
OpenStudy (anonymous):
did you use a calculator??
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OpenStudy (anonymous):
or long math??
OpenStudy (pulsified333):
yeah calculator
OpenStudy (anonymous):
ok cool
OpenStudy (pulsified333):
on the test he said to leave it as the setup to find the answer as the answer
OpenStudy (anonymous):
ok thats cool
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OpenStudy (anonymous):
so do you get it??
OpenStudy (pulsified333):
yeah
OpenStudy (anonymous):
alright dude goodnight then
OpenStudy (pulsified333):
night