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Mathematics 9 Online
OpenStudy (pulsified333):

Assume that n = 13, and p = 3/9. Find the probability of at least 3 successes and at least 3 failures.

OpenStudy (pulsified333):

@Musicdude

OpenStudy (anonymous):

ok

OpenStudy (pulsified333):

I've tried two different methods but neither worked

OpenStudy (anonymous):

ok that is a binomial probability within a binomial probability i think. i need to think for this

OpenStudy (anonymous):

hold up i might be wrong

OpenStudy (pulsified333):

ok

OpenStudy (anonymous):

ok its binomial probability with parameters

OpenStudy (anonymous):

have you seen this yet? or heard of it?

OpenStudy (pulsified333):

I dont think so

OpenStudy (anonymous):

ok its a hard concept so let me see how i can explain it

OpenStudy (anonymous):

wow im stumped... i cant explain it but do you have a ti-84 or higher?

OpenStudy (anonymous):

i can show you haw to get the answer

OpenStudy (pulsified333):

um I don't because the professor doesn't allow calculators

OpenStudy (anonymous):

O.O

OpenStudy (anonymous):

omg

OpenStudy (anonymous):

hes evil

OpenStudy (pulsified333):

imagine the test

OpenStudy (anonymous):

im in stat 3 and we use computers

OpenStudy (anonymous):

but we code our own calculations

OpenStudy (anonymous):

ok thats tricky to do without a calculator

OpenStudy (anonymous):

and i really dont have a pencil because im on my way home on the bus with my phone

OpenStudy (anonymous):

nor paper

OpenStudy (pulsified333):

it's okay

OpenStudy (anonymous):

sorry dude ask @ganeshie8 or @satellite73

OpenStudy (pulsified333):

I got the answer

OpenStudy (anonymous):

ok cool how?

OpenStudy (pulsified333):

:D

OpenStudy (anonymous):

i just want to see

ganeshie8 (ganeshie8):

I don't see how you can possibly do it with out using calculator http://www.wolframalpha.com/input/?i=%5Csum%5Climits_%7Bk%3D3%7D%5E%7B10%7D+%28%2813+choose+k%29*%283%2F9%29%5Ek+*+%286%2F9%29%5E%2813-k%29%29

OpenStudy (anonymous):

lol same

OpenStudy (pulsified333):

basically do the Bernoulli trials for each one from 3-13 for both and then multiple them together to get .8611

OpenStudy (anonymous):

it would be 2 separate probabilities

OpenStudy (pulsified333):

yeah then multiply them together

OpenStudy (anonymous):

i think it would be two different answers because it is 2 different events

OpenStudy (anonymous):

because both cant exist together

OpenStudy (pulsified333):

No because it says 3 success "and" 3 failures. Which in Finite math means multiply

OpenStudy (anonymous):

but then where are the 8 trails go? if there aren't success not faliure

OpenStudy (anonymous):

thats the thing

OpenStudy (anonymous):

thats whats tricky because it creates a parameter

OpenStudy (anonymous):

i know the answer but its really complex to get to without a calculator

OpenStudy (anonymous):

is you did use the Bernoulli trials you would use 3-10 because you have to account for the "at least 3 faliures"

OpenStudy (anonymous):

you there?

OpenStudy (pulsified333):

yeah

OpenStudy (anonymous):

im guessing it would be around .86 just because i know

OpenStudy (anonymous):

and i used a calculator

OpenStudy (pulsified333):

yeah

OpenStudy (anonymous):

is that around what you got??

OpenStudy (pulsified333):

yeah i got .8611

OpenStudy (anonymous):

yeah thats it

OpenStudy (anonymous):

did you use a calculator??

OpenStudy (anonymous):

or long math??

OpenStudy (pulsified333):

yeah calculator

OpenStudy (anonymous):

ok cool

OpenStudy (pulsified333):

on the test he said to leave it as the setup to find the answer as the answer

OpenStudy (anonymous):

ok thats cool

OpenStudy (anonymous):

so do you get it??

OpenStudy (pulsified333):

yeah

OpenStudy (anonymous):

alright dude goodnight then

OpenStudy (pulsified333):

night

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