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Very small question (will probably take a second), help me understand this textbook example. ~Calculus Limits & Derivatives.
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How is that 0?
Why is \(\lim_{x\to a}(x-a)\neq 0\)? \(a-a=0\).
So, substitute 0 in \[\lim_{x \rightarrow a}(x-a) \] to get a-a=0?
substitute 0 for a*
Since \(f(x)=x-a\) is continuous you can do that.
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Ok. Thanks! :)
Continuity of \(f(x)=x-a\) can be proven using \(\epsilon\text{-}\delta\) definition of limit.
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