Question

Pythagorean Thereom 3-D!!!
Picture attached!

Answer 1

@angel12310

You have to find DG first.

\[DG^2 = DC^2 + CG^2\]

\[AG^2 = DG^2 + AD^2\]

Can you figure it out now?

Answer 2

Nope...

Answer 3

@angel12310

You just have to substitute the names of lines for their lengths, try!

Answer 4

:( ok

Answer 5

@angel12310

Just give it another bash, if you really, really have trouble please don't hesitate to ping me. c:

Answer 6

@angel12310

That equation is not possible.

\[DG^2 = 5^2 + 12^2\]

Answer 7

IDK!!!

Answer 8

DG^2= 25+ 144

Answer 9

DG^2=169

Answer 10

Square root of 169

Answer 11

13

Answer 12

DG^2=13?

Answer 13

13.0 cm?

Answer 14

Okay,

\[DG^2 = 5^2 +12^2\]

Therefore DG = \[\sqrt 169=13\]

\[AG^2 = DG^2 + 4^2\]

=\[AG^2 = 13^2 +4^2\]

=\[AG^2 = 185\]

\[\sqrt 185 = 13.6\]

Therefore the answer is 13.6

Answer 15

ok thx!

Answer 16

Remember that \[AG^2 = Dg^2 + 4^2\]

No problem! c:

Answer 17

Can u help me with a few more?

Answer 18

@angel12310

Sure, I'll be on for a bit longer! c: