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Simplify: ln e1
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\(\ln(e^1)\) ?
like that?
yea like that
\(e^1\)?? must be an algorithmically generated question a human being would write (e\)
yes
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Ok, you know that any number raised to an exponent of \(\color{black}{\LARGE _{^1}}\), is that number itself: \(\color{black}{a^1=a}\)
oh wow that was so simple.
And, just like: \(\log_a(a)=1\) \(\log_e(e)=\ln(e)=?\)
so it would be e?
again, I mentioned a property: \(\large \log_a(a)=1\) And number e also satisfies that property: So, the expression below would be equivalent to what? \(\large\log_e(e)=?\)
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1
Yes
So, \(\large\ln(e)=\log_e(e)=1\)
thankyou thankyou thankyouu !
\(\color{blue}{\Large \mathbb{Y}\unicode{x22a1} \mathbb{U}~~ \mathbb{WELC} \unicode{x22a1}\mathbb{ME}}\)
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