Question

What is the equation of the oblique asymptote?
h(x) = x^2-3x-4/x+1
a y=x+4
b y=x^2-3
c y=x
d y=x-4

Answer 1

HI!!

Answer 2

divide

Answer 3

you will get a quotient and a remainder
ignore the remainder, the quotient is your obliques asymptote

Answer 4

So the answer is D?

Answer 5

@misty1212

Answer 6

that's correct

Answer 7

awesome Thanks!

Answer 8

well it's not awesome as the equation doesn't have an oblique asymptote...

if you factor the numerator

\[\frac{x^2 - 3x -4}{x +1} = \frac{(x - 4)(x + 1)}{x +1} \]

you'll find the equation simplifies to a linear form

y = x - 4

and there is a point of discontinuity at x = -1

hope it helps