Question

(4x+f(x)) / (3−g(x)) can i get help to find the derivative using the quotient rule, thanks.

Answer 1

@Loser66

Answer 2

We have to use the quotient rule?

Alright well we know it can be written as \(\Large \frac{b(x)a'(x) - a(x)b'(x)}{b(x)^2}\)

Knowing the top is a(x) and the bottom is b(x)

\[\large a(x) = 4x + f(x)\]
\[\large a'(x) = 4 + f'(x)\]
\[\large b(x) = 3 - g(x)\]
\[\large b'(x) = -g'(x)\]

so

\[\large \frac{(3 - g(x))(4 + f'(x)) - (4x + f(x))(-g'(x))}{(3 - g(x))(3 - g(x))}\]

There is't really TOO much to simplify from there...but if you need to you can

Answer 3

thank you! i have been stuck on this problem for a while now.