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Mathematics 10 Online
OpenStudy (narissa):

help

OpenStudy (narissa):

OpenStudy (anonymous):

What do you think it is?

OpenStudy (narissa):

is it d?

OpenStudy (anonymous):

No, do you want me to guide you through it or do you want to try one more time?

OpenStudy (calculusxy):

\[\large (2.5 \times 9)(10^{-8} \times 10^{-9})\] However, remember that the bases (in scientific notation) needs to be between 1 and 10.

OpenStudy (anonymous):

^

OpenStudy (narissa):

explain

OpenStudy (calculusxy):

Your product is really 22.5 (which is not between 1 and 10) so you need to move the decimal place to the left to make it 2.25 (which is between 1 and 10).

OpenStudy (calculusxy):

When you do that, you need to do an extra step

OpenStudy (narissa):

wow confusing

OpenStudy (anonymous):

When you multiply 2.5 and 9, you get 22.5, which is not in scientific notation, so you must change it back

OpenStudy (calculusxy):

\[\huge 2.25 \times 10^1 \times 10^{-18}\]

OpenStudy (narissa):

so a

OpenStudy (calculusxy):

\[\huge 10^1 \] is needed because you moved the decimal one place to the left. Now the reverse can be applied to when you need to move the decimal place to the left. \[\huge 10^{-1}\]

OpenStudy (anonymous):

No, it will still be negative

OpenStudy (calculusxy):

Not really what is \[\large 1 + {-18} \]

OpenStudy (calculusxy):

That will be your exponent, while 2.25 is your base.

OpenStudy (narissa):

-17

OpenStudy (calculusxy):

Good.. so what's your final answer now?

OpenStudy (narissa):

thanks both of u

OpenStudy (narissa):

c

OpenStudy (anonymous):

Yes

OpenStudy (calculusxy):

Correct!

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