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OpenStudy (narissa):
OpenStudy (anonymous):
What do you think it is?
OpenStudy (narissa):
is it d?
OpenStudy (anonymous):
No, do you want me to guide you through it or do you want to try one more time?
OpenStudy (calculusxy):
\[\large (2.5 \times 9)(10^{-8} \times 10^{-9})\]
However, remember that the bases (in scientific notation) needs to be between 1 and 10.
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OpenStudy (anonymous):
^
OpenStudy (narissa):
explain
OpenStudy (calculusxy):
Your product is really 22.5 (which is not between 1 and 10) so you need to move the decimal place to the left to make it 2.25 (which is between 1 and 10).
OpenStudy (calculusxy):
When you do that, you need to do an extra step
OpenStudy (narissa):
wow confusing
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OpenStudy (anonymous):
When you multiply 2.5 and 9, you get 22.5, which is not in scientific notation, so you must change it back
OpenStudy (calculusxy):
\[\huge 2.25 \times 10^1 \times 10^{-18}\]
OpenStudy (narissa):
so a
OpenStudy (calculusxy):
\[\huge 10^1 \] is needed because you moved the decimal one place to the left.
Now the reverse can be applied to when you need to move the decimal place to the left.
\[\huge 10^{-1}\]
OpenStudy (anonymous):
No, it will still be negative
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OpenStudy (calculusxy):
Not really what is
\[\large 1 + {-18} \]
OpenStudy (calculusxy):
That will be your exponent, while 2.25 is your base.
OpenStudy (narissa):
-17
OpenStudy (calculusxy):
Good.. so what's your final answer now?
OpenStudy (narissa):
thanks both of u
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