Question posted below...
\[\large A = \left\{ \frac{ 4 }{ 7 } , 1, \frac{ 5 }{ 2 }, \frac{ 11 }{ 7 }, 7 \right\}\] \[\large B = \left\{ \frac{ 4 }{ 7 },\frac{ 7 }{ 4 },4,7 \right\}\] If n is a member of both set A and set B above, which of the following must be true? I. n is an integer II. 4n is an integer III. n = 4 (A) None (B) II only (C) I an II only (D) I and III only (E) I, II, and III
@Vocaloid
\[\large A = \left\{ \frac{ 4 }{ 7 } , 1, \frac{ 5 }{ 2 }, 4, \frac{ 11 }{ 7 }, 7 \right\}\] \[\large B = \left\{ \frac{ 4 }{ 7 },\frac{ 7 }{ 4 },4,7 \right\}\]
well, first step is to see which elements are common to both sets
Well I know that III should be correct since 4 appears on both sets.
nope, not quite.
4/7, 4, and 7 are common, so n could be any one of these three options
You're looking at the second one right?
Wait.. would it be none?
that's correct
since n has three possibilities, we know that III is out
Thank you!
no problem ^_^~
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