Question

got stuck... 2sin(squared) theta =1

Answer 1

okay

Answer 2

help me solve

Answer 3

umm wait

Answer 4

Do you mean 2sin^2theta=1

Answer 5

yes

Answer 6

\[2 \sin ^2\theta=1,or~1-\cos 2\theta=1\]
\[\cos 2\theta=0=\cos (2n+1)\frac{ \pi }{ 2 }\]
\[2 \theta=\left( 2n+1 \right)\frac{ \pi }{ 2 },\theta=\left( 2n+1 \right)\frac{ \pi }{ 4 }\]

Answer 7

here n is an integer.

Answer 8

thanks

Answer 9

2sin²(θ) = 1

sin²(θ) = 1/2

sin(θ) = ± 1/√2

sin(θ) = ± (√2)/2


First case: sin(θ) = + (√2)/2

θ = π/4

θ = π - (π/4) = 3π/4


Second case: sin(θ) = - (√2)/2

θ = 2π - (π/4) = 7π/4

θ = π + (π/4) = 5π/4


→ Solution = { π/4 ; 3π/4 ; 5π/4 ; 7π/4 }

Answer 10

Thanks princess!

Answer 11

yw

Answer 12

You are quite welcome @Jhulian if you no longer have any questions about this subject please do close the question. Thank you very much.(: