Question

How many solutions does the equation have? 2(2x+5)=4(x+3) A. one solution B. infinite solutions C. no solution

Answer 1

2(2x+5)=4(x+3)

4x+10=4x+12

Answer 2

Is that true for any values of x?

Answer 3

no solution?

Answer 4

Yes

Answer 5

Thank You!

Answer 6

Yw !

Answer 7

How many solutions does the equation have?

a+5=1/5(5a+25)

A.
one solution

B.
infinite solutions

C.
no solution
What about this one i think infinite solutions

Answer 8

\(\large\color{black}{ a+5=\frac{1}{5}(5a+25)}\) like this?

Answer 9

yes

Answer 10

then you are correct - "infinte solutions" is the right answer.

Answer 11

Because when you expand the right side, you get:

\(\large\color{black}{ a+5=\frac{1}{5}(5a+25)}\)

\(\large\color{black}{ a+5=a+5}\)

and that is true for any value of a.

Answer 12

Thank you again!

Answer 13

You welcome, again! :)

Answer 14

I have 3 more

Answer 15

if you could check them

Answer 16

Alright...

Answer 17

How many solutions does the equation have? 4x + 2(x-3)=8x + 12 A. one solution B. infinite solutions C. no solution

Answer 18

what did you choose?

Answer 19

A?

Answer 20

Yes, correct!

Answer 21

Thank You!!

Answer 22

yw

Answer 23

Which expressions would complete this equation so that it has infinitely many solutions?

8 + 2(8x – 6) =

Choose exactly two answers that are correct.

A.
2(4x + 7)

B.
9x – 10

C.
16x – 4

D.
4(4x – 1)

Answer 24

and your choice was?

Answer 25

C and D?

Answer 26

Or A and D?

Answer 27

8 + 2(8x – 6) =
8 + 16x – 12 =
16x – 4.

` same = same ` ----> ` 8 + 2(8x – 6) = 16x - 4 `

C is right

Answer 28

So C and D?

Answer 29

8 + 2(8x – 6) =
8 + 4(4x – 3) =
8 + 4(4x – 1 - 2) =
8 + 4(4x – 1) + (-2)(4) =
8 + 4(4x – 1) -8 =
4(4x – 1) =

Answer 30

yes, C and D

Answer 31

Thanks Again!!! I have one more

Answer 32

k

Answer 33

What is the best way to classify each equation? Column AColumn B 1. 8x + 24=2(4x+12) 2. 5x + 18-x=2(2x+8) 3. 7(3x-2)=20x-13 4. 3x + 2(x-10)=5(x-4) A. identity B. contradiction C. neither

@SolomonZelman

Answer 34

Can you write the Columns more clearly please?

Answer 35

dont worry about the columns... Column A is with the long equations and Column B is A.
identity
B.
contradiction
C.
neither

Answer 36

Column A Column B
1. 8x + 24=2(4x+12)
2. 5x + 18-x=2(2x+8)
3. 7(3x-2)=20x-13
4. 3x + 2(x-10)=5(x-4)

like this?

Answer 37

what you have underneath column B is suppose to be under Column A and under Column B is suppose to be this A.
identity
B.
contradiction
C.
neither

Answer 38

Column A Column B
8x+24=2(4x+12) Identity
5x+18-x=2(2x+8) Contradiction
7(3x-2)=20x-13 Niether
3x+2(x-10)=5(x-4)

like this?

Answer 39

yes

Answer 40

`(When you expand 1st row, 1st column)`
8x+24=2(4x+12) \(\longrightarrow\) 8x+24=8x+24

Answer 41

`(Expand 2nd row, 1st column)`
5x+18-x=2(2x+8) \(\longrightarrow\) 5x+18-x=4x+16

`(Subtract x from 5x: 5x-x=4x)`
5x+18-x=4x+16 \(\longrightarrow\) 4x+18=4x+16

Answer 42

So at this point you should be able to tell me
whether A is an *identity* (true for all values of x),
a *contradiction* (true for NO values of x - i.e. always false)
OR *Niether* (not contradition or identity - i.e. has 1 solution)

Answer 43

`(Expand 3rd row, 1st column)`
7(3x-2)=20x-13 \(\longrightarrow\) 21x-14=20x-13

`(Subtract 20x from both sides)`
21x-14=20x-13 \(\longrightarrow\) x-14=13

`(Add 14 to both sides)`
x-14=13 \(\longrightarrow\) x=27

(and this is Niether)

Answer 44

`(Expand 4th row, 1st column)`
3x+2(x-10)=5(x-4) \(\longrightarrow\) 3x+2x-20=5x-20

`(Add like terms on the left side)`
3x+2x-20=5x-20 \(\longrightarrow\) 5x-20=5x-20

Can you identify this one as either:
*identity*, *contradiction*, or *Neither*

Answer 45

sorry I had to leave but im back @SolomonZelman

Answer 46

Ok, read over my posts, please.
This should clarify every thing....

Answer 47

ok

Answer 48

so
1.A
2.B.
3.C
4.A?

Answer 49

yes,

Identity
Contradition
Neither
Identity

*CORRECT!*

Answer 50

THANK YOU!!!!!!!

Answer 51

Anytime:)

Answer 52

I got 100%

Answer 53

Nice to hear that:)

Answer 54

have a good night!