Question

x^6-64
facotr as a diffrence of square and cube
please help

Answer 1

is it -4(x+6) . my firend got that answer. didnt tell me how to do it tho

Answer 2

x^6-64 = (x^3)^2 - (8)^2 = ( x^3 + 8) * (x^3 - 8)

That is the factorization into 2 squares.

Answer 3

>>is it -4(x+6) NO

Answer 4

Factor x^6-64 as difference of 2 cubes.

Factoring pattern is attached.

Answer 5

im going to try the cube and see what i get

Answer 6

x--4(x^3+4x+16)

Answer 7

i think

Answer 8

x^6-64 = [ (x^2)^3 - (4)^3) ]

= [ x^2 - 4 ] * [ (x^2)^2 + (x^2)*4) + (-4)^2 ]

Answer 9

(x-4)(x^2+4x+4^2)

Answer 10

[ x^2 - 4 ] * [ (x^2)^2 + (x^2)*4) + (-4)^2 ] =
(x^2 -4) (x^4 + 4x^2 + 16)

Answer 11

okay i see what i did wrong . i dont know where i got a 3 from. thank you for the help . both of you

Answer 12

I am uncertain about the instructions.

Taking it from the top:

x^6-64 = (x^3)^2 - (8)^2 =

( x^3 + 8) * (x^3 - 8) =

(x + 2) ( x^2 -2x + 4) (x - 2) (x^2 + 2x + 4)

Answer 13

You are welcome.