Question

227

229

271

317

349

You can use all the types of methods to try and get the answer, but you MUST use 1997, and keep it in that order no matter what. Please help, too hard 4 me...

Answer 1

@whpalmer4

Answer 2

@ParthKohli

Answer 3

@Luigi0210

Answer 4

@dan815

Answer 5

@UnkleRhaukus

Answer 6

What is the question?

Answer 7

You have to make those numbers by using 1997

Answer 8

you can't rearrange them, but you can use anything you want to make it the number. You can use powers, square roots, etc.

Answer 9

I can't get it at all, so I was wondering if anyone else could help me with this xD

Answer 10

interesting :)

Answer 11

Can't do it xD

Answer 12

Closest I got was 220

Answer 13

can we rearrange the number 1,9,9,7?

Answer 14

nope xD

Answer 15

it has to stay in that specific order

Answer 16

(1 + 9) x 9 x √7 = 238.1

Answer 17

SO CLOSE

Answer 18

this is hard, how did you get 220?

Answer 19

(19+9)+7^2

Answer 20

(1 + √9) x 9 x 7 = 252

Answer 21

(19 x 9) + 7^2 = 220

Answer 22

yep, thats what I did xD

Answer 23

closest thing I got xD

Answer 24

(1 x 9 x 9) + √7 = 214.3

Answer 25

:o

Answer 26

\[\sqrt{\sqrt{1\times 9^9\times7}}=228.2\]

Answer 27

wow, thats really close /:

Answer 28

So annoying... this stupid assignment.

Answer 29

can you use powers of numbers other than 1,9,9,7?

Answer 30

if you mean, can you square it or "double it" yes you can

Answer 31

but 1997 has to stay in place/ keep the same structure.

Answer 32

so you can use 1997 as many times as you want but it keeps that structure, like 1*9*9*7*1*9*9....etc?

Answer 33

oh... no thats not usable xD

Answer 34

so you can only use 1997 once then?

Answer 35

mhmm

Answer 36

(1 x 9 x 9) + √7 = 214.3

Answer 37

but wouldn't it be defeating the purpose if you use powers of 3 then? even tho you are multiplying it 3 times... your using a number not in that set..

Answer 38

probs over thinking it.

Answer 39

uhhh xD

Answer 40

I dunno xD Its hard just trying to do it the legit way xD

Answer 41

227 is a prime number, so I suppose the manipulation of the numbers you have should reflect that...

I'm struggling quite a bit as well, but maybe you should work backwards? add 1, 9 or 7 to your target number and try to factorize it to get hints on how to create it..

Answer 42

:o thats a good idea, i'll try that now xD

Answer 43

I just got 226 :P

Answer 44

gg no re jade is a genius

Answer 45

can we do something like this-
\[1 \times \sqrt{9},\sqrt[\infty]{9},7 =317\]?

Answer 46

yep

Answer 47

so 317 is done :)

Answer 48

:o thank you xD

Answer 49

But I don't get how it becomes 317 xD

Answer 50

\[1 \times \sqrt{9}=1 \times 3=3\]\[\sqrt[\infty]{9}=1\]\[7=7\]

joining all :)
317

Answer 51

:o

Answer 52

thank you for your explanation xD

Answer 53

np (:

Answer 54

and thank you jade, i'll make sure to use your methods :D

Answer 55

@imqwerty

You can join the numbers? don't you have to add or multiply?

Answer 56

OH

Answer 57

idk? @Epicteatime said yes so i did it :)

Answer 58

Yeah, you have to add them or multiply them to get the actual number, sorry Jade I didnt see how you got it xD

Answer 59

not jade, imqwerty

Answer 60

1×9√,9√∞,7=317

Answer 61

ah, so no joining then, that would have made it easier. :c

Answer 62

2^2 • 3 • 19 = 228 - (227 +1) 2 • 113 = 226 = (227-1) 22 • 5 • 11 = 220 = (227 - 7) 2 • 32 • 13 = 234 = (227 +7) 22 • 59 = 236 = (227 +9) 2 • 109 = 218 = (227 - 9)

Answer 63

yeah, it would have

Answer 64

lauren, thats not how you do it xD Thanks for your effort though :D

Answer 65

I'm sure this is actually a simple question at it's heart, I doubt we need fancy, doctorate level thesis' on how this could work.

The numbers we have are 1 , 9 , 9 , 7 , they have to be dealt with in that order, but they can be subtracted and added to each other, as well as divided and multiplied.

We can use any number we wish when "doubling" or calculating to the power, right @epicteatime ?

Answer 66

@Epicteatime

I got ONE answer.

\[1 * 9^{2.5} - 9 - 7 = 227 \]

Answer 67

sorry, I went to eat dinner xD Im back now tho :D

Answer 68

and thank you for answering one xD

Answer 69

sadly there's still like, 4 :P

Answer 70

@Epicteatime

Hope you enjoyed dinner haha,

I know, but once one goes down, surely the rest should be easier? XD

Answer 71

maybe, maybe

Answer 72

xD

Answer 73

which one are you doing jade?

Answer 74

I'm trying to do the second one now, it's only a difference of 2 so...

Answer 75

alright, i'll do 271 then :D

Answer 76

holy crap...

Answer 77

I Just got 271

Answer 78

but I still need to do something with 7 xD

Answer 79

So, I need to subtract 14 from \[9^{2.5}\] in order to get 229.

How can I make 14?

---

Also, congrats! I'm sure you can turn the 7 into a 0 somehow...

Answer 80

so which ones do you have left? haha

Answer 81

229

271

317

349

Answer 82

those :3

Answer 83

ahh okiee

Answer 84

yush :3

Answer 85

I GOT 271!!!!

Answer 86

oh wait...

Answer 87

1997-99-1/7

Answer 88

uhh

Answer 89

hmmm....

Answer 90

1-99/7=271? xD

Answer 91

can we use the numbers 1, 9, 9 and 7 as many times as we'd like?

Answer 92

nope xD

Answer 93

sadly xD

Answer 94

damn ahahha

Answer 95

but can we rearrange stuff to make like 99 and 17 and stuff?

Answer 96

99 yes, 17 no xD

Answer 97

you have to keep 1997 in that order