How do you identify the oblique asymptote for a function y=x^2-4/x+1
not all functions have oblique asymptote if the degree of the numerator one larger than the denominaotr degree then you can find slant(oblique)asy.
\[\huge\rm y=\frac{ x^\color{ReD}{2}-4 }{ x^{\color{blue}{1}}+1 }\] highest degree of the numerator is 2 and the denominator is one so we can find oblique asy divide x^2-4 by x+1 using long division or synthetic division btw for this question you can factor x^2 -4
so the degree of the numerator is bigger than that which is the denominator so this one will be a slant how do you find a slant
so factoring x^2 - 4 would be x- 2?
no that wouldn't work sorry we should divide
oh okay thats fine
synthetic division or long which one is easy for u?
synthetic division does the one become -1 or stay the same
yes right we should solve for x x+1 = 0 x=-1 |dw:1444312769154:dw| x^2 -4 is same as x^2 +0x - 4 we should write highest degree to lowest so that's why i wrote 0 there
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