Calculate the electric field at the center of the circle:
can the circle be the sphere? say @CShrix
@lall I'm not sure. It does not specify sphere. I would assume that the field inside a sphere is 0, given that the material is conductive.
read one of the statements in the middle, there is written that the 2 half circles are separated by thin insulator thus there is no charge conductance b/w the 2 half circles.... thus if the circles are charged then the charges shold lie on the boundary of the half circles so that the 2 half circles have an electric field uniformly on the centre...
could it be so?
i think u just need to apply the formula for electric field for the individual charges for half of the radius each
Wouldn't that just yield the normal equation: \[E=\frac{kQ}{r^2}\]
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