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Physics 6 Online
OpenStudy (anonymous):

Calculate the electric field at the center of the circle:

OpenStudy (anonymous):

can the circle be the sphere? say @CShrix

OpenStudy (anonymous):

@lall I'm not sure. It does not specify sphere. I would assume that the field inside a sphere is 0, given that the material is conductive.

OpenStudy (anonymous):

read one of the statements in the middle, there is written that the 2 half circles are separated by thin insulator thus there is no charge conductance b/w the 2 half circles.... thus if the circles are charged then the charges shold lie on the boundary of the half circles so that the 2 half circles have an electric field uniformly on the centre...

OpenStudy (anonymous):

could it be so?

OpenStudy (anonymous):

i think u just need to apply the formula for electric field for the individual charges for half of the radius each

OpenStudy (anonymous):

Wouldn't that just yield the normal equation: \[E=\frac{kQ}{r^2}\]

OpenStudy (anonymous):

|dw:1444331060490:dw|

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